In this tutorial, we will learn how to write C Program to find the Sum of Diagonals of Matrix. as the matrix contains two diagonals, we will consider one as the main and another as the opposite.
Note that the number of rows and number of columns of a matrix must be equal that is it should be 2×2 or 3×3, etc. In other words, the matrix must be a square matrix.
We will look through the C program and find the sum of the main & opposite diagonal elements of an MxN Matrix. For example:
Consider a matrix of 2×2 matrix,
2 3
6 5
Output:
Sum of the main diagonals = 2+5 = 7
Sum of the opposite diagonals = 3+6 = 9
C Program to find the sum of the diagonal elements in a matrix
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 | #include <stdio.h> void main() { int arr[10][10]; int i, j, m, n, sum1 = 0, sum2 = 0; printf("Enter the order of the matix: "); scanf("%d %d", &m, &n); //Checking the condition to see if m is equal to n if (m == n) { printf("Enter the elements for the matrix: \n"); for (i = 0; i < m; ++i) { for (j = 0; j < n; ++j) { scanf("%d", &arr[i][j]); } } // Adding the diagonals for (i = 0; i < m; ++i) { sum1 = sum1 + arr[i][i]; sum2 = sum2 + arr[i][m - i - 1]; } printf("\nThe sum of the main diagonal: %d\n", sum1); printf("The sum of the opposite diagonal: %d\n", sum2); } else printf("The order entered is not square matrix."); } |
Output:
As you can see in the program that if..else statement has been used to check if the order entered is a square matrix or not (m == n).